Call function received as a parameter in Javascript

Question

I have the following code with a function:

var f1;

var getFunction = function (f2) {
    f1 = f2;   
}

Later in the code, I need to call f1 (that was actually received as a parameter). Note that I don't know the function's name when I call it.

How do I make this call?

Later in the code where? Why don't you know the name? By your example, you know it's either f1 or f2. Did you try something and experience failure? Is there something async involved? The question is very unclear. — user1106925
– user1106925, Commented Jul 7, 2016 at 12:08
When you assign a function to f1, guess what... its name is f1. — deceze
– deceze ♦, Commented Jul 7, 2016 at 12:09
@Kaiido: Do you honestly not understand the point he was making? — user1106925
– user1106925, Commented Jul 7, 2016 at 12:14
@Kaiido ...a name by which you can call the function is... – I was trying to keep it simple and straight forward. There isn't a lot of space in comments to list all caveats and asterisks and it doesn't make it easier to understand either. — deceze
– deceze ♦, Commented Jul 7, 2016 at 12:19

Ashkan Mobayen Khiabani · Accepted Answer · 2016-07-07 12:07:21Z

2

function test(){
     alert(1);
}
var f1;

var getFunction = function (f2) {
    f1 = f2; 
    f1();  
}

getFunction(test);

Here is the DEMO

answered Jul 7, 2016 at 12:07

Ashkan Mobayen Khiabani

34.4k35 gold badges112 silver badges187 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

epascarello · Accepted Answer · 2016-07-07 12:09:18Z

1

This is no different than callbacks in Ajax call or anywhere else where you pass around a reference to a function. You just execute it via the variable that you store the function in.

var f1;

var setFunction = function (f2) {
    f1 = f2;   
}

setFunction( function(x) { console.log(x); } );

f1("test");

If you need to execute it with scope, than you need to use .apply() or .call()

answered Jul 7, 2016 at 12:09

epascarello

208k20 gold badges206 silver badges246 bronze badges

Comments

chiappins · Accepted Answer · 2016-07-07 12:08:55Z

0

var f1;

var getFunction = function (f2) {
    f1 = f2;   
}
var b = function(){}
getFunction(b);
f1();

answered Jul 7, 2016 at 12:08

chiappins

2213 silver badges17 bronze badges

1 Comment

bryan kennedy Over a year ago

Could you provide some context to your answer, explaining how it works and addresses the question?

Collectives™ on Stack Overflow

Call function received as a parameter in Javascript

3 Answers 3

Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related