How to get a link from <a> python parser

Question

<a class="button button-mini" href="www.example-link.com.c"><b>TEXT</b></a>

I'm creating Python parser, and i need to get link from this tag. I tried this, but result was "None":

link = table.find_all('td')[1].a.href
link = table.find_all('td')[1].a.link

Using Beautiful Soup 4 & Python 3.5

Nander Speerstra · Accepted Answer · 2016-07-18 11:11:08Z

1

I think that it's a pretty simple question where you are just missing parameters. It should be written as:

link = table.find_all('td')[1].a.get('href')

Edit note

Just noticed after answering that a user has responded to you as comment... Don't want to steal any credits.

Nander Speerstra

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answered Jul 18, 2016 at 11:01

Rui Couto

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