int path[10]={'_', '_', '_', '_', '_', '_', '_', '_', '_', '_'};
for (int b=0;b<=9;b++) {
cout << path[b];
}
When I try to run this to display a horizontal line it just shows a lot of 9s and 5s. But however if I run this one
for (int b=0;b<=9;b++) {
cout << '_';
}
It seems to do the work. I know I can just use the 2nd bulk of code but I need to display it using the array.
path is an array of int, when you print out its elements the int value (i.e. the ascii code 95 for '_') will be printed out. If you want it to be printed out as char, you should change the declaration from
int path[10]={'_', '_', '_', '_', '_', '_', '_', '_', '_', '_'};
to
char path[10]={'_', '_', '_', '_', '_', '_', '_', '_', '_', '_'};
In the first example you declare path as an array of int and it gets interpreted by std::cout like an int (ASCII code for _ is 95). To make it work, you need to change the declaration to:
int path[10]={'_', '_', '_', '_', '_', '_', '_', '_', '_', '_'};
In the second example you output '_' to std::cout, which is a char type and is displayed as you expected.
charandint.