How to capture repeating groups in Regex (for C#) [duplicate]

Question

I've to detect and extract from a string a repeating group of characters and list one part of each captured group.

Here is an example of string to parse: "za e eStartGood1Endds qStartGood2Endsds df"

My Regex is: ".*?(?::Start(.+)End.*?)+"

Expecting groups captured expected: Good1, Good2, etc

My Regex capture is wrong: it seems that (?::Start(.+) is considered as group to capture...

May I miss something? Thanks!

I guess you just need Start(.*?)End. No idea what your input really looks like. Have you got actual asterisks there or is it formatting? — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 22, 2016 at 11:25
I tell you: use my regex. Regex.Matches(input, @"Start(.*?)End").Cast<Match>().Select(p => p.Groups[1].Value).ToList(); — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 22, 2016 at 11:47
Wiktor, i need a complete Regex syntax to be used in my project. I can't use Link. And this question has no duplicate as far as I know: I need to extract these values several times. — Francois
– Francois, Commented Jul 22, 2016 at 12:07

baddger964 · Accepted Answer · 2016-07-22 12:21:35Z

0

This regex do the job :

/(?<=Start)(.+?)(?=End)/g

edited Jul 22, 2016 at 12:21

answered Jul 22, 2016 at 11:30

baddger964

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5 Comments

Francois Over a year ago

Thanks @baddger, I tried this regex ((?<=Start)(.+?)(?=End))* (without ** for bold font) and i get all characters one by one like this: "z", "a", " ", "e", etc ... Other idea?

baddger964 Over a year ago

try the updated answer :p

Francois Over a year ago

Yes, I'm closer now... :) Just need to hide start and end groups... Your regex returns "za e eStart", "Good1", "Endds dqStart", "Good2", "Endsds df". But thanks for this simple syntax with <= and =. I tried to hide them but no return with this one: "(?:<=Start)(.+?)(?:=End)"

Francois Over a year ago

Ok, simpler than I thought. You were right Baddger. Regex is: "Start(.+?)End". No need to define a repeating group to get all instances...

baddger964 Over a year ago

so Wiktor Stribiżew say the good answers :p

Andrei Tătar · Accepted Answer · 2016-07-22 11:27:01Z

0

Why not use this pattern: \*{2}Start\*{2}(.*?)\*{2}End\*{2}

For this input string: za e e**Start**Good1**End**ds dq**Start**Good2**End**sds df, it captures Good1 and Good2.

You can play with it here: https://regex101.com/r/dG0dX6/2

answered Jul 22, 2016 at 11:27

Andrei Tătar

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1 Comment

Francois Over a year ago

Sorry Andrew, you were right too...

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