django channels message.reply_channel no attribute send

Question

I've been trying to get my head around the channels of Django and I can't get my message to be sent to my websocket.

Here is my consumers.py

import logging
from django.contrib.sites.models import Site
from django.utils import timezone
from channels import Group
from .models import *
import json

def send_free(message):
    try:
        pi = PInformation.objects.get(
            pk=message.content.get('pk'),
        )
    except Parkplatzinformationen.DoesNotExist:
        logging.error("PI not found!")
        return

    try:
        message.reply_channel.send({
        "text": 1,
    })
    except:
        logging.exception('Problem sending %s' % (pi.name))

My routing.py

from channels.routing import route

from RESTAPI.consumers import send_free

channel_routing = [
    route('send-free',send_free),
]

I'm getting the error AttributeError: 'NoneType' object has no attribute 'send'. It does however get the PInformation object so it does work a "bit". I'm calling it right after I'm saving the object.

Could you please give me some hints? The Getting Started guide uses it like I try to.

Raja Simon · Accepted Answer · 2016-07-24 19:11:52Z

1

I assume you are calling "send-free" from your view like this...

Channel('send-free').send({'message': 'your message'})

Then send_free doesn't have the message.reply_channel...

In other word once the WebSocket packet is sent to us by a client then message takes the reply_channel attribute from it. That will use to reply message back to client... ( to frontend maybe )

So do you really want to send message...? then again send using consumers...

edited Jul 24, 2016 at 19:11

answered Jul 24, 2016 at 18:03

Raja Simon

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6 Comments

dowu Over a year ago

Yes you are correct I'm calling the send-free the way you described it. However I do not get what do you mean by repeating the process.

Raja Simon Over a year ago

@dowu Repeat Channel("cons").send(dict) and also I edited the answer..

dowu Over a year ago

Okay so I call Channel("otherchanel").send(dict) instead of message.reply_channel.send again? Isn't "otherchannel" supposed to be linked to a function and so I'm stuck with the same problem?

Raja Simon Over a year ago

What message your are trying to send back and why ? You are calling the consumer function from your view then you are expecting your consumer to send back the message back to view ?

dowu Over a year ago

I want to send a dict to the client after the object has been updated so I can display that information on a homepage (retrieving it with javascript). (thank you for your patience)

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