Tkinter print specified item from list in loop

Question

I've code like below:

from tkinter import *

root = Tk()
root.title("sample program")

def print_item_from_list(event):
    print(variable)

list = [1, 2, 3, 4, 5]
seclist = []
print(list)
for i in range(0,5):
    variable = list[i]
    sample = Label(text=variable)
    sample.pack()
    sample.bind('<Enter>', print_item_from_list)

root.mainloop()

What I want to achieve is that everytime my pointer enter label 'Sample', specified item form list is printed (i.e. when I hover over label '2', I want second object from my list to get printed). I tried already changing variable to list[i] (Just for tests if it would work) and creating second list and appending to it, but with no luck. My guess is it's somehow connected to Tkniter behaviour.

stackoverflow.com/questions/14259072/…

Billal BEGUERADJ
– Billal BEGUERADJ

2016-07-25 05:33:44 +00:00
Commented Jul 25, 2016 at 5:33 — Billal BEGUERADJ
– Billal BEGUERADJ, Commented Jul 25, 2016 at 5:33

dsgdfg · Accepted Answer · 2016-07-25 06:21:06Z

2

With your code :

from tkinter import *

root = Tk()
root.title("sample program")

def print_item_from_list(event):
    print(event.widget.config("text")[-1])


list = [1, 2, 3, 4, 5]
seclist = []
print(list)
for i in range(0,5):
    variable = list[i]
    sample = Label(text=variable)
    sample.pack()
    sample.bind('<Enter>', print_item_from_list)

root.mainloop()

answered Jul 25, 2016 at 6:21

dsgdfg

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Comments

Aran-Fey · Accepted Answer · 2016-07-25 04:55:32Z

1

You can make use of closures:

for i in range(0,5):
    variable = list[i]
    sample = Label(text=variable)
    sample.pack()
    def connect_callback(variable):
        sample.bind('<Enter>', lambda event:print(variable))
    connect_callback(variable)

This creates a new callback function with a fixed value for each label. In your code, all callbacks refer to the same variable, but with this solution every callback has its own variable.

answered Jul 25, 2016 at 4:55

Aran-Fey

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