I've got this regex:
(/(\d{2})(\d{3})(\d{2})/g;
What I want to do is to replace every 2, when every 3 and when every 2 again character with a " " while typing. Which means if I type "123" it should be formatted to "12 3" and if I type "12345" it should be formatted to "12 123 "
However I get a spacing only after every 7 character. Here's a jsfiddle: http://jsfiddle.net/K4WXc/257/
Help would be highly appreciated!
I have modified your fiddle as shown below:
return v.replace(/^(\d{2})(\d{1,3})(\d{0,2}).*/, function (match, a, b, c) {
return a + ' ' + b + (c == '' ? '' : ' ' + c);
});
Keeping in mind that just before this block, you have removed any non-digits, this block expects just digits (no spaces).
It matches 2 digits at the beginning: ^(\d{2})
Then 1 to 3 as the next capture group: (\d{1,3})
If there are 3 in that 2nd group, it will capture up to 2 more: (\d{0,2})
Anything more than that will be discarded: .*
The important part of this that enables it to match "incomplete" entries as you type is that it matches even if you haven't typed all 3 digits of the 2nd group, or both of the 3rd group.
NOTE: the main problem with your original replace was the missing first param that represents the whole matched string.
123456and1234567,123465789?return v.replace(/\d(?=(\d{3})+$)|^\d(?=\d{2}$)/g, "$& ");and let know if that meets your requirements.v.replace(/^(\d{2}) ?(\d{3})?(?=\d)/g, "$1 $2 ");