Javascript Regex returns null, node.js

Question

I try to select a string based on regex, I use node.js ,here is my code :

var string = ' [email protected]    Tel:   +971000000000 0500000348';
var regExp = '\\(\\+971\\|00971\\|05\\)\\d\\{1,12\\}';
var find = string.match(regExp)[0];
console.log(find);

I need to select only numbers that starts with +971 , 00971, 05 , this returns null, (I had to escape twice coz it throws an error if I don't) this regex works fine: '\\+971\\d{1,12}';

user3335966 · Accepted Answer · 2016-08-04 00:51:54Z

1

I don't know node.js specific, so sorry if my answer would be stupid, but what about:

var string = ' [email protected]    Tel:   +971000000000 0500000348';
var regExp = /(\+971|00971|05)\d{1,12}/g;
var find = string.match(regExp);
return find;

answered Aug 4, 2016 at 0:51

user3335966

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James · Accepted Answer · 2016-08-04 00:48:42Z

0

(\+971|00971|05)(\d{1,12})

Get group 2 and you should get what you want. I am not sure why you need to escape also. It is working for me without escaping.

answered Aug 4, 2016 at 0:48

James

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