Decode a base64 string to a decimal string

Question

I have a string say FhY= which has been encoded to hex. So when run

>>> b6 = 'FhY='
>>> b6.decode('base64')
'\x16\x16'

This is a hex string that once converted should be 22 22. This result has been proven on the site https://conv.darkbyte.ru/. However, I cannot seem to do a proper conversion from base64 to decimal representation. Some of the challenges I am facing are

Expectation of decimal being an int. I just want base 10
Incorrect values. I have tried the following conversions base64 > base16(Convert a base64 encoded string to binary), base64 > binary > decimal(Convert hex string to int in Python) both of which have failed.

Please assist.

@IgnacioVazquez-Abrams probably because he needs an example :P struct.unpack('H','\x16\x16') maybe? — Joran Beasley
– Joran Beasley, Commented Aug 10, 2016 at 16:11
Thanks @JoranBeasley. seems to work. However is there a solution that does not involve a two step process? One straight from base64 to base10? — Magondu
– Magondu, Commented Aug 10, 2016 at 16:14

Marco · Accepted Answer · 2016-08-10 16:18:13Z

3

You need to convert each byte from the decoded string to its decimal value. So this should solve it:

b6 = 'FhY='
' '.join([ str(ord(c)) for c in b6.decode('base64') ])

Results in 22 22

answered Aug 10, 2016 at 16:18

Marco

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2 Comments

Leonid Over a year ago

Thanks, looks good. Is this function reversible? How could I map the resulting base-10 text back to the base-64 string?

Marco Over a year ago

@Leonid you can reverse the function by using ''.join(map(lambda x: chr(int(x)), '22 22'.split())).encode('base64')

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