I have 2 lists which contains exact similar dates but the formatting is different. How can I compare those 2 lists are equal ignoring the format of the date?
Eg:
List 1:
[2016-07-22, 2016-07-20, 2016-07-18, 2016-07-18, 2016-07-18, 2016-07-20, 2016-07-18]
List 2:
[22.07.2016, 20.07.2016, 18.07.2016, 18.07.2016, 18.07.2016, 20.07.2016, 18.07.2016]
Let me know if there is anyway I can do this.
Updated:
You can use this logic to compare two date.
SimpleDateFormat sf1= new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat sf2= new SimpleDateFormat("dd.MM.yyyy");
Date date1=sf1.parse("2016-07-18");
Date date2=sf2.parse("18.07.2016");
boolean bol=date1.compareTo(date2)==0;
System.out.println(bol);//true if two dates are equal, false if two date are not equal
Example
Date[] dl1={sf1.parse("2016-07-22"), sf1.parse("2016-07-20"), sf1.parse("2016-07-18"), sf1.parse("2016-07-18"), sf1.parse("2016-07-18"), sf1.parse("2016-07-20"), sf1.parse("2016-07-18")};
Date[] dl2={sf2.parse("22.07.2016"), sf2.parse("20.07.2016"), sf2.parse("18.07.2016"), sf2.parse("18.07.2016"), sf2.parse("18.07.2016"), sf2.parse("20.07.2016"), sf2.parse("18.07.2016")};
List<Date> l1= Arrays.asList(dl1);
List<Date> l2= Arrays.asList(dl2);
for(int i=0;i<l1.size();i++){
if(l1.get(i).compareTo(l2.get(i))==0){
System.out.println("Date matched");
}else{
System.out.println("Date did not matched");
}
}
Output:
Date matched
Date matched
Date matched
Date matched
Date matched
Date matched
Date matched
Parse the dates:
List<String> list1 = // ...
DateTimeFormatter formatter1 = DateTimeFormatter.ofPattern("yyyy-MM-dd");
List<LocalDate> dates1 = list1.stream()
.map(s -> LocalDate.parse(s, formatter1))
.collect(Collectors.toList());
// same with list2 and an adapted formatter
List<String> list2 = // ...
DateTimeFormatter formatter2 = DateTimeFormatter.ofPattern("dd.MM.yyyy");
List<LocalDate> dates2 = list2.stream()
.map(s -> LocalDate.parse(s, formatter2))
.collect(Collectors.toList());
boolean equal = dates1.equals(dates2);
List<String>right ?