How to Parse JSON to [String: AnyObject] in Swift

Question

I am trying to do a simple JSON string to Object conversion. Here is the code:

let u = "somehost.com/api/1/ipa/2"
let url = NSURL(string: u )!

let data = NSData(contentsOfURL: url)!

let parsed: AnyObject? = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.AllowFragments) 

if let json = parsed as? [String: AnyObject]{
    // never enters this if statement.
}

But it will not unwrap correctly. Seems to me that this should be much simpler. Could someone please help? Also using "Xcode 7.3 and swift 2.2".

I want to avoid using a third party library.

If it does not pass the optional binding it's most likely not [String:AnyObject]. Show the beginning of the JSON. — vadian
– vadian, Commented Aug 27, 2016 at 4:49
It might be a list of dicts like: as? [[String: AnyObject]] { ... — Ozgur Vatansever
– Ozgur Vatansever, Commented Aug 27, 2016 at 4:54
api link is not in production, but the json string that is returned is {"a":"b","c":"d"}. Also it is not in a list. @NDoc — xazb
– xazb, Commented Aug 27, 2016 at 5:07

Sanju · Accepted Answer · 2016-08-27 05:10:47Z

1

Sample Json Parsing Fetch and read like this easy and simple understanding process. Hit the below link you will see the response as dictionary and inside dictionary there is an array.......

   let WebURL = "http://api.randomuser.me/"

    let url2 = NSURL(string:WebURL)

    let data = NSData(contentsOfURL: url2!)

    do
    {

       let dictionary = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments) as! NSMutableDictionary

        print(dictionary)

        let arrayOfValues = dictionary .objectForKey("results") as! NSMutableArray

        print(arrayOfValues)


        for var i = 0; i<arrayOfValues.count; i++ {


            let resultDictInsideArray = arrayOfValues.objectAtIndex(i)

            let NameDict = resultDictInsideArray.objectForKey("name")!

            let locDict = resultDictInsideArray.objectForKey("location")!



            print(NameDict.objectForKey("title")!)
            print(locDict.objectForKey("street")!)



        }


    }catch {

    print("error")


    }

If your URL has spaces write code for URL like this

 let url = NSURL(string: stringUrl.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())!)!

answered Aug 27, 2016 at 5:10

Sanju

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1 Comment

xazb Over a year ago

Does not work... I am getting this error Could not cast value of type '__NSCFString' to 'NSMutableDictionary'

Yann Bodson · Accepted Answer · 2016-08-27 04:46:43Z

0

Are you sure what is returned is not an array rather than an object?

Have you tried this:

if let json = parsed as? [AnyObject]{
}

answered Aug 27, 2016 at 4:46

Yann Bodson

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Comments

Lovina Hajirawala · Accepted Answer · 2017-02-09 09:38:03Z

       func getDataFromServer(myGetUrl : URL) {
        let url = myGetUrl
        //create the session object
        let session = URLSession.shared

        //now create the URLRequest object using the url object
        let request = URLRequest(url: url )

        //create dataTask using the session object to send data to the server
        let task = session.dataTask(with: request as URLRequest, completionHandler: { data, response, error in

            guard error == nil else {
                print(error as Any)
                return
            }

            guard let data = data else {
                return
            }

            do {
                //create json object from data
                if let json = try JSONSerialization.jsonObject(with: data, options: []) as? [[String:AnyObject]] {
                    //print(json)
                    self.getResponsedata = json
                    //print("Here: \(self.getResponsedata)")
                    self.getDelegate.GetdataReceivedFromServer(data: self.getResponsedata , url : myGetUrl)
                }
            } catch let error {
                print(error.localizedDescription)
            }
        })
        task.resume()
    }
}

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