Drupal 8 Guzzle Format Query String

Question

Forgive me for my ignorance, this is my first attempt at Drupal 8 and I'm not a good php developer to begin with. But I've been reading and searching for hours. I'm trying to do a post using the new Guzzle that replaces the drupal_http_request(). I've done this using Curl but can't seem to get this going in the right direction here. I'm just not "getting it".

Here is a sample of the array I have that pulls data from a custom form. I also tried this with a custom variable where I built the string.

$fields = array(
   "enroll_id" => $plan,
   "notice_date" => $date,
   "effective_date" => $date,
);

$client = \Drupal::httpClient();
$response = $client->post('myCustomURL', ['query' => $fields]);
$data = $response->getBody()->getContents();
try { 
drupal_set_message($data);
} catch (RequestException $e) {
watchdog_exception('MyCustomForm', $e->getMessage());
}

This indeed returns the result of REJECTED from my API in $data below - but it doesn't append the URL to included the query => array. I've tried numerous combinations of this just putting the fully built URL in the post (that works with my API - tested) and I still receive the same result from my API. In the end what I'm trying to accomplish is

https://myCustomURL?enroll_id=value&notice_date=12/12/12&effective_date=12/12/12

Any direction or tips would be much appreciated.

yelrug · Accepted Answer · 2016-09-06 14:21:18Z

2

Thanks for the responses guys. I was able to get it to work correctly by changing a few things in my post. First changing client -> post to a request('POST', XXX) and then changing "query" to "form_params" as "body" has been deprecated.

http://docs.guzzlephp.org/en/latest/quickstart.html#query-string-parameters

$client = \Drupal::httpClient();
$response = $client->request('POST','https://myURL.html', ['form_params' => $fields]);
$data = $response->getBody()->getContents();

answered Sep 6, 2016 at 14:21

yelrug

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1 Comment

Steve Mulvihill Over a year ago

I had to change $client->post to request('POST, XXX) as well to get it working.

Ricardo Velhote · Accepted Answer · 2016-09-05 10:00:19Z

0

Using $client->post will send a POST request. By looking at the URL that you tested directly you want a GET request.

Either use $client->get or $client->request with the GET parameter. More information and examples in the Guzzle documentation.

answered Sep 5, 2016 at 10:00

Ricardo Velhote

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