I'm trying to loop a statement/output in linux. So in my ssh directory if I do ls. There is a file call hello.c which prints Hello James. What i'm trying to do is a for loop that prints it 4 times.
This is what i've tried.
for((int i=1;i<=4;i++));
do
./hello.c
echo $i
done
However nothing is printing.
Bash as a programming language, is dynamically typed, so there are no type declarations. So you can remove the type declaration from the line bellow:
for((int i=1;i<=4;i++));
^^^
i.e. change it to
for((i=1;i<=4;i++));
Additionally, are you sure that you can call the program by saying ./hello.c? This is usually the source file and is not executable.
Using the shell command line you type (in the shell prompt)
for((i=1;i<=4;i++)); do echo "hello"; done
# outputs "hello" four times
Whatever you need to create a script, you should edit a file:
echo '#!/bin/bash' > my_script.sh
echo 'for((i=1;i<=4;i++)); do echo "hello"; done' >> my_script.sh
and then change the permissions to make it executable.
chmod +x my_script.sh
./my_script.sh
Make sure to read one of the many tutorials about shell (bash) programming, http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html is a good one.