Enable input field after checkbox is checked in list of checkboxes

Question

I have a list of data getting from database, and i want to enable input field on checked checkbox. However its working only with the first line. Here is HTML code:

<?php
    require_once('inc/config.php');
    include 'verification/verify_form_details.php';
?>
<html>
<head>
  <title>getElementById example</title>
  <script type="text/javascript" src="js/jquery-2.1.3.min.js"></script>
</head>
<body>
    <?php 
        $result2 = getProcessID();
    ?>
    <label>Process: <small style="color:red;">*</small>             
    <?php 
        while ($row = mysql_fetch_array($result2))
        {
            $row[0] = cleanOutputData($row[0]);
    ?>      
    <div>       
        <label>
        <input type="checkbox" class="checkbox" name="process[]" id=<?php echo $row[0] ?>  value=<?php echo $row[0]?> /><?php echo $row[0] ?>
        </label>                                        

        <label>
        <input type="text" class="field" disabled name="number[]" id=<?php echo $row[0] ?> />
        </label>

    </div>
    <?php
        }
        mysql_free_result($result2);
    ?>
    </label>
</body>
</html>

And javascript function:

<script>
    $(document).ready(function () {
            $('.checkbox').change(function() {
                $('.field').attr('disabled',!this.checked)
            });
    });
</script>

Any ideas how i can do it? Thank you

@guradio I tried class and now after pressing on one checkbox its enabling all fields. edited my question also — Yevgeniy Bagackiy
– Yevgeniy Bagackiy, Commented Sep 6, 2016 at 3:00
use $(this).parent().next().find('.field').attr('disabled',!this.checked) — guradio
– guradio, Commented Sep 6, 2016 at 3:03
@guradio now all the fields are staying disabled even when checkbox is checked — Yevgeniy Bagackiy
– Yevgeniy Bagackiy, Commented Sep 6, 2016 at 3:10

guradio · Accepted Answer · 2016-09-06 03:15:32Z

4

$('.checkbox').change(function() {
  $(this).parent().next().find('.field').prop('disabled', !$(this).is(':checked'))
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<label>
  <input type="checkbox" class="checkbox" name="process[]" id=v alue=/>
</label>

<label>
  <input type="text" class="field" disabled name="number[]" id=/>
</label>


<label>
  <input type="checkbox" class="checkbox" name="process[]" id=v alue=/>
</label>

<label>
  <input type="text" class="field" disabled name="number[]" id=/>
</label>


<label>
  <input type="checkbox" class="checkbox" name="process[]" id=v alue=/>
</label>

<label>
  <input type="text" class="field" disabled name="number[]" id=/>
</label>

Use class instead of ID
Use this context to refer to changed element

answered Sep 6, 2016 at 3:15

guradio

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