Using segmented control to switch tableView

Question

I'm trying to change my table view cell when the segmented control is changed here is what I have now

internal func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    var returnValue = 0

    switch(segmentedC.selectedSegmentIndex)
    {
    case 0:
        returnValue = rest.count
        break
    case 1:
        returnValue = fullMenu.count
        break
    default:
        break

    }

    return returnValue
}

I have this for my numberOfRowsInSection and cellForRowAtIndexPath

 func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    var cell = tableView.dequeueReusableCellWithIdentifier("food") as! restTableViewCell
    var cell2 = tableView.dequeueReusableCellWithIdentifier("fullM") as! fullmenuTableViewCell
    switch(segmentedC.selectedSegmentIndex)
    {
    case 0:
        let res: Rest!
        res = rest[indexPath.row]

        var img: UIImage?

        if let urls = foo.imageString{
            img = foodViewController.imageCache.objectForKey(urls) as? UIImage

        }
        dispatch_async(dispatch_get_main_queue()) {
            cell.setupViews(res)

        }

        break
    case 1:
            cell2.textLabel?.text = fullMenu[indexPath.row]
        break

    default:
        break

    }
    return cell
}

Also I have an IBAction for the segmented control

@IBAction func seg(sender: AnyObject) {

    switch(segmentedC.selectedSegmentIndex)
    {
    case 0:
        tableView.reloadData()
        break

    case 1:
        tableView.reloadData()
        break
    default:
        break

    }

}

But when I change the segment only one cell from the index 0 show up in the index 1

nishith Singh · Accepted Answer · 2016-09-07 12:32:51Z

2

In your cellForRowAtIndexPath you are always returning cell you are never returning cell2. Try returning cell2 in your second case.

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
var cell = tableView.dequeueReusableCellWithIdentifier("food") as! restTableViewCell
var cell2 = tableView.dequeueReusableCellWithIdentifier("fullM") as! fullmenuTableViewCell
switch(segmentedC.selectedSegmentIndex)
{
case 0:
    let res: Rest!
    res = rest[indexPath.row]

    var img: UIImage?

    if let urls = foo.imageString{
        img = foodViewController.imageCache.objectForKey(urls) as? UIImage

    }
    dispatch_async(dispatch_get_main_queue()) {
        cell.setupViews(res)

    }

    break
case 1:
        cell2.textLabel?.text = fullMenu[indexPath.row]
        return cell2
    break

default:
    break

}
return cell
}

answered Sep 7, 2016 at 12:32

nishith Singh

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7 Comments

Sagaya Abdul Over a year ago

Yes this worked thank you!. But is this the best way to use segmented control with tableviews?

nishith Singh Over a year ago

Depends on your use case dude i don't know your use case so i can't be sure if this approach is best or not but i can suggest some improvements like you don't need cases in your IBAction func seg(sender: AnyObject) just calling reload once will do, and for an added bonus the break behaviour is by default for switch in swift so if you remove all the break it will work exactly the same.

Sagaya Abdul Over a year ago

Am experiencing slow loading when cell is tapped any idea why?

nishith Singh Over a year ago

Can you share your didSelectRowAtIndexPath code? Might be some issue there.

Sagaya Abdul Over a year ago

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {                  var foo:Food!         foo = food[indexPath.row]         var selectedCell:UITableViewCell = tableView.cellForRowAtIndexPath(indexPath)!         selectedCell.contentView.backgroundColor = UIColor.clearColor()         performSegueWithIdentifier("Vc", sender: foo)      }

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