Sorting array by variable number of columns

Question

Say I have an array

var originalArray = [1,2,3,4,5,6,7]

I want to display to apply function orderToColumn (originalArray, numberofcolumn) to get a return value like so

Array [ 1, 4, 7, 2, 5, undefined, 3, 6, undefined ]

the point being I want to be able to display my array in the following format:

1 4 7
2 5
3 6

Heres my attempt so far: https://jsfiddle.net/042o7rv9/ The array could be of any size and the numberofcolumn>=1.

Can you give another example with a longer or a shorter array? — Sebastian Simon
– Sebastian Simon, Commented Sep 16, 2016 at 20:19
Does originalArray always start with 1 and is it always sorted? In other words, why is there no gap for the missing 0? — Sebastian Simon
– Sebastian Simon, Commented Sep 16, 2016 at 20:31
nah the array could be objects, i used sorted numbers simply for explanation purposes. anyways i figured it out on my own. seemed to be more of an bootstrap/css error when rendering rather than algorithm error — Sean Dawford
– Sean Dawford, Commented Sep 16, 2016 at 20:37

Alex Kudryashev · Accepted Answer · 2016-09-16 20:28:57Z

2

You can do something like this.

var a = [1,2,3,4,5,6,7];
function orderToColumn(arr,col){
  var len = col*Math.ceil(arr.length / col);
  console.log(len);
  var newArr=[];
  for(var i = 0;i<col;i++){
    for(var j=0;j<len/col;j++){
      newArr.push(arr[j*col+i]);
    }
  }
  return newArr;
}
var b = orderToColumn(a,3);
console.log(b); // [1, 4, 7, 2, 5, undefined, 3, 6, undefined]

answered Sep 16, 2016 at 20:28

Alex Kudryashev

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Comments

Redu · Accepted Answer · 2016-09-16 20:48:25Z

0

You might do functionally as follows;

function columnize(a,n){
  var count = Math.ceil(a.length/n);
  return a.reduce((p,c,i) => i%count === 0 ? p.concat([[c]]) : (p[p.length-1].push(c),p),[]);
}

var originalArray = [1,2,3,4,5,6,7],
           result = columnize(originalArray,3);
console.log(result);

answered Sep 16, 2016 at 20:48

Redu

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