I want to grab the RSS feed content from a site and display it in my website with different filtering options.
Can anyone put a php script which can grab the content from there and show
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possible duplicate of Best way to parse RSS/Atom feeds with PHP and some others. Consider using an RSS parser or DOM. Also, please increase your Accept Rate.Gordon– Gordon2010-10-18 10:47:40 +00:00Commented Oct 18, 2010 at 10:47
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2 Answers
SO is for asking specific questions related to programming. Even though your question is related to programming you are not asking a specific question.
A quick google search for "PHP read RSS feeds gives you a list of very good links which can get you started.
How to Read an RSS Feed With PHP – screencast
Try out the example and see if it fits your requirement. If you have any specific questions then come back to SO and I am sure everyone will be glad to help.
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something like this:
rss.php
<?php
// enable php_xsl extension
$xml = new DomDocument;
$xml->load("http://www.gamestv.org/rss.php?type=news&limit=8");
$xsl = new DomDocument;
$xsl->load("RSSFeed.xsl");
$xp = new XsltProcessor();
$xp->importStylesheet($xsl);
if($html = $xp->transformToXML($xml)) echo $html;
?>
RSSFeed.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/rss/channel">
<xsl:for-each select="/rss/channel/item">
<div style="padding-bottom:10px; padding-top:10px;"><a>
<xsl:attribute name="title"><xsl:value-of select="title"/></xsl:attribute>
<xsl:attribute name="href"><xsl:value-of select="link"/></xsl:attribute>
<xsl:value-of select="title"/>
</a></div>
<div><xsl:value-of disable-output-escaping="yes" select="description"/></div>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
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