If my string is
Size : 93743 bytes Time elapsed (hh:mm:ss.ms): 00:00:00.156
How do I match the value that appears after the (hh:mm:ss.ms): ?
00:00:00.156
I know how to match if there are more characters following the value, but there aren't any more characters after it and I do not want to include the size information.
Like so:
<?php
$text = "Size : 93743 bytes Time elapsed (hh:mm:ss.ms): 00:00:00.156";
# match literal '(' followed by 'hh:mm:ss.ms' followed by literal ')'
# then ':' then zero or more whitespace characters ('\s')
# then, capture one or more characters in the group 0-9, '.', and ':'
# finally, eat zero or more whitespace characters and an end of line ('$')
if (preg_match('/\(hh:mm:ss.ms\):\s*([0-9.:]+)\s*$/', $text, $matches)) {
echo "captured: {$matches[1]}\n";
}
?>
This gives:
captured: 00:00:00.156
$ anchors the regex to the end of the string:
<?php
$str = "Size : 93743 bytes Time elapsed (hh:mm:ss.ms): 00:00:00.156";
$matches = array();
if (preg_match('/\d\d:\d\d:\d\d\.\d\d\d$/', $str, $matches)) {
var_dump($matches[0]);
}
string(12) "00:00:00.156"
00:00:00:1 or 00:00:00:22?
...00:100 and ...00:220 in those cases.
...00:100 - is that to say $ tells the preg_match that it should stop looking at that point, or to continue looking until the end of the string? I think I need something that says to stop the match after the last \d