Take a list, say for example this one:
a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
and write a program that prints out all the elements of the list as the list [1,1,2,3,5] that are less than 5. Currently it prints as
1
1
2
3
5
My code
a = [1,1,2,3,5,8,13,21,34,55,89]
count = 0
for i in a:
if i<=5:
count+=1
print(i)
To have it print out as a list, keep it as a list. You can use list comprehension to accomplish this:
>>> a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
>>> [i for i in a if i<=5]
[1, 1, 2, 3, 5]
If we use print, it still looks the same:
>>> print([i for i in a if i<=5])
[1, 1, 2, 3, 5]
filter
filter(lambda x: x<=5, a) or, in either py2 or py3, one could use list(filter(lambda x: x<=5, a)).If you want all to print out all the element that great and equal to 5 then you are doing it right. But if you want to print out less then 5 you want:
for i in a:
if i < 5:
count += 1
print(i)
You should have the if condition be more strict if you want only element smaller than 5. It should be if i<5: instead of i<=5.
If you want to store the elements in a new list, see the example below.
a = [1,1,2,3,5,8,13,21,34,55,89]
new_list=[]
for i in a:
if i<5:
new_list.append(i)
print new_list
[1,1,2,3,5]instead of1 1 2 3 5? If so, it's probably advisable to drop the part of the question that just recaps the homework problem you were on when this came up. It's confusing as currently presented.[1,1,2,3,5]is less than or equal to 5...