I'm quite new at VBA. I've used it in excel for a couple macros, but this one is way above my head. I'm looking to create a macro that will find the appropriate column, then based on the value in this columns, changes the values in three other columns. I already have a static macro:
Sub AdjustForNoIntent()
'Adjusts columns Role(U) (to C-MEM), REV Profile Follow-up Date(AJ) (to N/A) and deletes Follow-up Date(Y) when column Survey: Intent to Participate = No
Dim lastrow As Long
Dim i As Long
lastrow = Range("AE" & Rows.Count).End(xlUp).Row
For i = 2 To lastrow
If Not IsError(Range("AE" & i).Value) Then
If Range("AE" & i).Value = "No" And Range("U" & i).Value = "MEM" Then
Range("U" & i).Value = "C-MEM"
Range("Y" & i).ClearContents
Range("AJ" & i).Value = "N/A"
ElseIf Range("AE" & i).Value = "No" And Range("U" & i).Value = "VCH" Then
Range("U" & i).Value = "C-VCH"
Range("Y" & i).ClearContents
Range("AJ" & i).Value = "N/A"
End If
End If
Next i
End Sub
But this is a shared workbook, so people are adding columns randomly and every time I need to go back to the code and modify the columns refereces. What I want is, for instance, to look for column with "Role" header in row A3 and to insert it where the macro looks for column "U". That way other users can add/delete columns but I won't have to modify the macro every time.
In other macros, I manage to have this thing working:
Function fnColumnNumberToLetter(ByVal ColumnNumber As Integer)
fnColumnNumberToLetter = Replace(Replace(Cells(1,ColumnNumber).Address, "1", ""), "$", "")
End Function
Dim rngColumn As Range
Dim ColNumber As Integer
Dim ColName As String
ColName = "Email Address"
Sheets("Tracking").Select
Set rngColumn = Range("3:3").Find(ColName)
ColNumber = Sheets("Tracking").Range(rngColumn, rngColumn).Column
Sheets("Combined").Range(ActiveCell, "W2").FormulaLocal = "=IF(ISERROR(INDEX(Tracking!$A:$A,MATCH(O:O,Tracking!" & fnColumnNumberToLetter(ColNumber) & ":" & fnColumnNumberToLetter(ColNumber) & ",0))), INDEX(Tracking!$A:$A,MATCH(U:U,Tracking!" & fnColumnNumberToLetter(ColNumber) & ":" & fnColumnNumberToLetter(ColNumber) & ",0)), INDEX(Tracking!$A:$A,MATCH(O:O,Tracking!" & fnColumnNumberToLetter(ColNumber) & ":" & fnColumnNumberToLetter(ColNumber) & ",0)))"
However, I am unable to link the latter to the first and much less to get it to find multiple columns. Any help is appreciated.
EDIT:
Following suggestions, here is the new code. Doesn't return an error, but doesn't do anything either. It loops through the c loop ok, but jumps from For i =2 ... line to End Sub.
Sub Adjust()
Dim lastrow As Long
Dim i As Long
Dim headers As Dictionary
Dim c As Long
Set headers = New Scripting.Dictionary
For c = 1 To Cells(3, Columns.Count).End(xlToLeft).Column
headers.Add Cells(3, c).Value, c
Next c
lastrow = Cells(headers.Item("Survey: Interest to Participate") & Rows.Count).End(xlUp).Row
For i = 2 To lastrow
If Not IsError(Cells(i, headers.Item("Survey: Interest to Participate")).Value) Then
If Cells(i, headers.Item("Survey: Interest to Participate")).Value = "No" And Cells(i, headers.Item("Role")).Value = "MEM" Then
Cells(i, headers.Item("Role")).Value = "C-MEM"
Cells(i, headers.Ittem(" Follow-up date")).ClearContents
Cells(i, headers.Item("REV profile follow-up date")).Value = "N/A"
ElseIf Cells(i, headers.Item("Survey: Interest to Participate")).Value = "No" And Cells(i, headers.Item("Role")).Value = "VCH" Then
Cells(i, headers.Item("Role")).Value = "C-VCH"
Cells(i, headers.Ittem(" Follow-up date")).ClearContents
Cells(i, headers.Item("REV profile follow-up date")).Value = "N/A"
End If
End If
Next i
End Sub

