I have a JavaScript string containing "true" or "false".
How may I convert it to boolean without using the eval function?
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24JSON.parse('true') will return boolean true and JSON.parse('false') will return boolean falseHari Das– Hari Das2017-01-02 07:10:56 +00:00Commented Jan 2, 2017 at 7:10
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this stuff solved everything like number and string format stackoverflow.com/a/42136805/5531595Rohman HM– Rohman HM2017-02-09 12:34:47 +00:00Commented Feb 9, 2017 at 12:34
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@HariDas Worked perfectly! I'm surprised the Boolean object wrapper doesn't properly convert "true" and "false" strings. I think it should be allowed an optional second parameter that tells it to attempt converting the string value to a booleanHaulinOats– HaulinOats2022-09-06 20:31:28 +00:00Commented Sep 6, 2022 at 20:31
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3 Answers
var val = (string === "true");
Case insensitive:
const val = (string.toLowerCase() === "true");
answered Oct 20, 2010 at 10:12
Ignacio Vazquez-Abrams
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11 Comments
hotshot309
This works. It's probably better to add
var before the declaration of val.
Vinch
Even better with a triple equals ===
Max Strater
Another improvement is to change "string" to "string.toLowerCase()". This allows for "string" to have other encodings of true like "True" and "TRUE".
stephenbayer
var val = string.match(/true/i); // case insensitive match
Andrew Philips
var val = string.match(/^(true|yes|t|y|1)$/i); /* case insensitive + many + whole word */
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You could simply have: var result = (str == "true").
1 Comment
simhumileco
result = result === "true"; Here the parentheses are unnecessary, but should check the type and value.If you're using the variable result:
result = result == "true";
1 Comment
simhumileco
If you're using the variable result:
result = result === "true"; Here the parentheses are unnecessary, but should check the type and value.