multi if and elseif statement in form

Question

I have a form on a single page, if it don't have a id I want it to insert. but if there is an id then update.

I am having difficulties getting the form values to display in the button.

I am also not sure my if or else if statement is plausible.

<?php
function myform(){
    if(isset($_POST['add'])) {
        if ($myform_id > 0) {
            //my insert query here      
            $btn_value = "add";
            $btn_name = "add";

        }elseif(isset($_POST['edit'])){
            //my update query here        
            $btn_value = "edit";
            $btn_name = "edit";
        } 
    }
}
?>

My form button

<input type="submit" name="<? $btn_name?>" value="<? $btn_value?>">

<input type="submit" name="<? $btn_name?>" value="<? $btn_value?>"> you are not echoing $btn_name — devpro
– devpro, Commented Sep 30, 2016 at 16:33
dont know, r u expecting, you will get $btn_name = "add"; without form submission? — devpro
– devpro, Commented Sep 30, 2016 at 16:35

namir · Accepted Answer · 2016-09-30 16:24:30Z

0

try this

<input type="submit" name="<?echo $btn_name;?>" value="<? echo $btn_value;?>">

answered Sep 30, 2016 at 16:24

namir

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1 Comment

user6879622 Over a year ago

@namiramir still says undefined variable on input

vaishali · Accepted Answer · 2016-10-04 13:33:19Z

0

within the php tag itself give the following statement

print "<input type='submit' name='$btn_name' value='$btn_value'>";

answered Oct 4, 2016 at 13:33

vaishali

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