How do I pass a variable into a URL in a Perl script?

Question

How do I pass a variable into a URL in a Perl script? I am trying to pass the variables in an array to url. For some reason it is not working. I am not sure what I am doing wrong. The code roughly looks like this:

@coins = qw(Quarter Dime Nickel);

foreach (@coins) {
  my $req = HTTP::Request->new(POST =>'https://url/$coins.com');
 }

This does not work as $coins does not switch to Quarter,Dime,Nickel respectively.

What am I doing wrong?

To point you in the right direction: $coins != @coins in your example above. — Susheel Javadi
– Susheel Javadi, Commented Oct 21, 2010 at 12:36

Sinan Ünür · Accepted Answer · 2010-10-21 02:37:36Z

7

First, variables do not interpolate in single quoted strings:

my $req = HTTP::Request->new(POST => "https://url/$coins.com");

Second, there is no variable $coins defined anywhere:

foreach my $coin (@coins) {
  my $req = HTTP::Request->new(POST => "https://url/$coin.com");
 }

Also, make sure to use strict and warnings.

You should also invest some time into learning Perl properly.

edited Oct 21, 2010 at 2:37

answered Oct 21, 2010 at 1:16

Sinan Ünür

118k15 gold badges201 silver badges347 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

mscha Over a year ago

Also, name the scalar value $coin, not $coins.

vol7ron Over a year ago

Or without having a loop variable, you may use $coin[n] or $_ in place of $coin

chrisaycock · Accepted Answer · 2010-10-21 01:15:42Z

1

Use

'https://url/' . $_  . '.com'

Instead of your

'https://url/$coins.com'

answered Oct 21, 2010 at 1:15

chrisaycock

38.1k15 gold badges94 silver badges128 bronze badges

Collectives™ on Stack Overflow

How do I pass a variable into a URL in a Perl script?

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related