Regular expression to match hash URL string

Question

I have a url route I want to match only has url parameter

router.get('/:id',function(req,res,next){
}

Now the problem is other url like test, favicon all matches this path. I want to match only url path which is hash like and other related hash strings which will be random.

%242a%2410%24mbh0scotTihKwL69eKwVBuSoAShai4Qo8yY0HLPRlh0Pq0ospfAcm

I have tried with regular expression but , i dont seem to get my regex to match.

[a-z0-9][-!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{50,}$

I want to match any string with special characters with length of 50 and above .Can anyone help me ? Thank you

I think you wanted to write ^[-a-zA-Z0-9!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{50,}$ or ^[a-zA-Z0-9][-a-zA-Z0-9!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{49,}$ — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Oct 10, 2016 at 10:43

Wiktor Stribiżew · Accepted Answer · 2016-10-10 10:52:24Z

I want to match any string with special characters with length of 50 and above

In this case, you may use the following pattern:

^[-a-zA-Z0-9!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{50,}$

However, if you need to require the first char to be an ASCII letter or digit, you can do it either by rewriting the pattern as this one:

^[a-zA-Z0-9][-a-zA-Z0-9!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{49,}$
 ^^^^^^^^^^^                                           ^^^^

Or by using a lookahead (so as to keep 50 as the min argument) (see this demo):

^(?=[a-zA-Z0-9])[-a-zA-Z0-9!$%^&*()_+|~=`{}\[\]:";'<>?,.\/]{50,}$

In all the cases, the main point is that you need to adjust the limiting quantifier at the end / shift the character classes boundaries and make sure you use ^, the start of string anchor if your substring is at the start of the string. If it is not, you should remove it.

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