Replace http://[...] with Link Without http:// in Link Text

Question

I'm using this preg_replace to find links in tweet text and it dutifully returns an HTML link but I wonder if it's possible to, in the same line, lose the http:// from the link text. For example:

$output .= preg_replace('@(https?://([-\w\.]+[-\w])+(:\d+)?(/([\w/_\.#-]*(\?\S+)?[^\.\s])?)?)@', '<a target="blank" rel="nofollow" href="$1" target="_blank">$1</a>', $status->text);

might return:

<a target="blank" rel="nofollow" href="https://kanyewest.com/">https://kanyewest.com</a>

but I'd really like it to return:

<a target="blank" rel="nofollow" href="https://kanyewest.com/">kanyewest.com</a>

That function works great, @Charlotte, except it strips the second part of the link where there is a '/' later on. For example 't.co/twJ6g0rqtz' comes back as just 't.co' in the link text. — Kevin Nugent
– Kevin Nugent, Commented Oct 13, 2016 at 13:39
Sorry, yes. Thanks @Charlotte. I just re-read the answer and found that. Awesome, perfect! — Kevin Nugent
– Kevin Nugent, Commented Oct 13, 2016 at 13:40
Possible duplicate of Show only the domain name when replacing a URL with hyperlink — Charlotte Dunois
– Charlotte Dunois, Commented Oct 13, 2016 at 13:41

DatBundah · Accepted Answer · 2016-10-13 13:34:23Z

-1

You could just use a Substring. http://php.net/manual/en/function.substr.php

answered Oct 13, 2016 at 13:34

DatBundah

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