How do you define a function during dynamic Python type creation

Question

(This is in Python 3 btw)

Okay so say we use type() as a class constructor:

X = type('X', (), {})

What I'm trying to find is how would type() accept a function as an argument and allow it to be callable?

I'm looking for an example of how this could be accomplished. Something along the lines of:

>>> X = type('X', (), {'name':'World', 'greet':print("Hello {0}!".format(name))}
>>> X.greet()
Hello World!

@juanpa.arrivillaga my overall project has to do with dynamic programming. I chose tags revolving around the main purpose behind the question so I would attract those who could answer with that mindset. — theDr34mer
– theDr34mer, Commented Oct 16, 2016 at 8:30

idjaw · Accepted Answer · 2016-10-16 07:31:15Z

2

You need to pass the function. In your code, you call the function, and pass the result.

Try:

def print_hello(self):
    print("Hello {0}!".format(self.name))

X = type('X', (), {'name':'World', 'greet': print_hello})

edited Oct 16, 2016 at 7:31

idjaw

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answered Oct 16, 2016 at 7:29

shx2

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1 Comment

theDr34mer Over a year ago

Oh so the function needs to be defined beforehand? That helps with that part, now I've gotta find a way to dynamically define a function. most likely with eval() i'm sure

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