Url argument with Django

Question

I'm having some problem with my url in Django (1.9)

Tried many way to solve it, but still the same type of error

Reverse for 'elus' with arguments '()' and keyword arguments '{u'council': u'CFVU'}' not found. 1 pattern(s) tried: ['elus/(?P<council>[A-B]+)$']

The actual code is this :

View :

class RepresentativeView(ListView):
    model = Representative
    template_name= 'lea/elus.html'
    context_object_name = 'represents'

    def get_queryset(self, council):

        return Representative.objects.filter(active=True).filter(council=council).order_by(order)

url :

url(r'^elus/(?P<council>[A-B]+)$', views.RepresentativeView.as_view(), name='elus'),

Template :

{% url 'elus' council='CFVU' %}

I've tried with **kwargs and other things. It work with **kwargs in another function with <pk> in url, and my query is based on the id. But here, with a string I can't find the solution.

Alasdair · Accepted Answer · 2016-10-16 14:13:02Z

1

You have [A-B] will only match the letters A and B.

If you only want to match uppercase letters you could do:

url(r'^elus/(?P<council>[A-Z]+)$

Or, a common approach is to use [\w-]+, which will match upper case A-Z, lowercase a-z, digits 0-9, underscores, and hyphens:

url(r'^elus/(?P<council>[\w-]+)$

edited Oct 16, 2016 at 14:13

answered Oct 16, 2016 at 12:07

Alasdair

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1 Comment

Etherliah Over a year ago

Thanks, and sorry for the waste of time ... This error was really stupid error.

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