4

I'm used to programming in javascript where I can do the following to pass an argument into an immediately-invoked function expression:

(function(twoSeconds) {
    // do something with "twoSeconds" here
})(2 * 1000);

So I expected to be able to do something similar in Go, as below. However, it doesn't seem to work.

func (twoSeconds) {
    // build error: "twoSeconds" undefined
}(time.Second * 2)

So I have to do this instead:

func () {
    twoSeconds := time.Second * 2
}()

Therefore, my question is how can I pass an argument into a Go IIFE? And if it's not possible, why not?

1 Answer 1

11

Function arguments in Go need types. So do the following:

func(twoSeconds time.Duration) {
    // use twoSeconds
}(time.Second * 2)
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1 Comment

Oh, of course, that's obvious now, I can't believe I missed that! Thanks for the help anyway, upvoted and accepted.

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