Angular2: Return an object in a resolver

Question

I have to make a check in my resolver, if it's fine, I reassign the object, otherwise, I return an observable with the value false.

Here is my code:

resolve(route: ActivatedRouteSnapshot, state: RouterStateSnapshot) {
    return this.callApi().subscribe((result) => {
        if (blabla === true) {
            return Observable.of(result);
        }
        this.router.navigate([ '/' ]);
        return Observable.of(false);
    });
}

The Observable.of(false) seems to work, I go to the homepage, but with Observable.of(result) , I don't get the result in my component ...

Thank you for your help

You shouldn't return anything in .subscribe(). What's this supposed to do btw? — martin
– martin, Commented Oct 26, 2016 at 13:34
I'm checking if the object has been disabled, in this case I go to the homepage with a message. — GuillaumeC
– GuillaumeC, Commented Oct 26, 2016 at 13:36
Finally I fount the solution, switchMap instead of subscribe — GuillaumeC
– GuillaumeC, Commented Oct 26, 2016 at 13:54

Meir · Accepted Answer · 2016-10-26 14:02:51Z

1

You don't even need switchMap, you have the result available. Note that you convert both result and false to observables, but you can return them directly.

return this.callApi().map(result => (blahblah ? result : false));

The side effect inside the caller is not a best practice, you can handle it outside:

resolve(...).filter(result => !result).subscribe(() => this.router.navigate([ '/' ]));

answered Oct 26, 2016 at 14:02

Meir

14.4k4 gold badges44 silver badges49 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Angular2: Return an object in a resolver

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related