Simple Syntax Error [duplicate]

Question

Python says it has a syntax error in this line " elif (i%7==0) or str.count(str(i),'7')>0: " and I cannot figure it out. I'm new to Python so it must be something simple.

k=int(input("enter the value for k:"))

n=int(input("enter the value for n:"))
if k>=1 and k<=9:
    for i in range(1,n+1):

          if (i%7==0) and str.count(str(i),'7')>0:
              print("boom-boom!")
            elif (i%7==0) or str.count(str(i),'7')>0:
                  print("boom")
                else: print(i)

elif and else should be indented at the same level as if — Cristian Lupascu
– Cristian Lupascu, Commented Nov 4, 2016 at 12:00
You have indentation problems. You ought to use a modern editor like PyCarm to avoid this. — Laurent LAPORTE
– Laurent LAPORTE, Commented Nov 4, 2016 at 12:02
If you are new, the first step is to study, not ask for answers. — TigerhawkT3
– TigerhawkT3, Commented Nov 4, 2016 at 12:03

Oyekanmi Owolabi · Accepted Answer · 2016-11-04 12:02:50Z

1

The issue is with your identation:

Make sure the "elif" is inline with your "if" and also your "else" statement. Python is sensitive to indentations and spaces.

if (i%7==0) and str.count(str(i),'7')>0:
    print("boom-boom!")
elif (i%7==0) or str.count(str(i),'7')>0:
    print("boom")
else: 
    print(i)

answered Nov 4, 2016 at 12:02

Oyekanmi Owolabi

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Comments

user671150 · Accepted Answer · 2016-11-04 12:02:08Z

0

Add proper indentation:

k=int(input("enter the value for k:"))

n=int(input("enter the value for n:"))
if k>=1 and k<=9:
    for i in range(1,n+1):
        if (i%7==0) and str.count(str(i),'7')>0:
            print("boom-boom!")
        elif (i%7==0) or str.count(str(i),'7')>0:
            print("boom")
        else: 
            print(i)

answered Nov 4, 2016 at 12:02

user671150

Comments

Laurent LAPORTE · Accepted Answer · 2016-11-04 12:05:46Z

0

Here is an improved solution:

k = int(input("enter the value for k:"))
n = int(input("enter the value for n:"))

if 1 <= k <= 9:
    for i in range(1, n + 1):
        text = str(i)
        if i % 7 == 0 and text.count('7'):
            print("boom-boom!")
        elif i % 7 == 0 or text.count('7'):
            print("boom")
        else:
            print(i)

answered Nov 4, 2016 at 12:05

Laurent LAPORTE

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