Selenium Webdriver, how to validate a string in a url

Question

Any help to validate a parameter in the url using selenium web driver + java

getCurrentUrl() = https://www.loca.com/usa/test/#/xxx

My url string is as above, and based on the url I need to enter a value on the loaded page, like lets say - I have zipcode field to enter zipcode value.

If url string contains 'usa' Enter zipcode as 12345 if url string contains canada Enter zipcode as Ab1233

BlackHatSamurai · Accepted Answer · 2016-11-10 21:42:19Z

1

If you are using Java, you can do something like:

String zipcode = "";
String currentUrl = "https://www.loca.com/usa/test/#/xxx"
//This will check to make sure USA is a part of the URL, and doesn't exist as another part of the URL.
if(currentUrl.contains("/usa/")){
   zipcode = "12345";
//Same here with Canada
} else if(currentUrl.contains("/canada/"){
   zipcode = "ab1233"; 
//You can continue pattern for any other countries
} else if(currentUrl.contains(...){
...

Just put the URL into a string, and then use the String method contains to check and see if USA in the string. If it is, use zip code, otherwise, do something else.

edited Nov 10, 2016 at 21:42

answered Nov 10, 2016 at 21:40

BlackHatSamurai

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6 Comments

ddavison Over a year ago

i'd recommend maybe a switch statement instead, just based on the context of changing zipcodes per country. they could add more. also, should probably use .contains("/usa/") in case another part of the url has usa in it (just for safety)

JeffC Over a year ago

This is fine until you have to support a bunch of countries... then the switch is much easier to read.

BlackHatSamurai Over a year ago

@JeffC Contains returns a boolean, so how exactly would propose you use a switch statement? From the Java docs "An if-then-else statement can test expressions based on ranges of values or conditions, whereas a switch statement tests expressions based only on a single integer, enumerated value, or String object."

JeffC Over a year ago

Using .contains() isn't required. There are several ways you can adapt this code to use a switch. See my answer for one of them.

BlackHatSamurai Over a year ago

@JeffC While I get that you can accomplish this with a switch statement, you are making it more complicated just to make it more "readable". To me this is poor programming. Stick with what is simple. I offered a solution that was around 7 lines of code. Your solution almost triples that. You also use regex, and so on. All this to make it more readable? Good programing is providing a simple solution that does the job. Tripling the code base just to make something more readable isn't a good idea in my opinion.

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JeffC · Accepted Answer · 2016-11-11 05:40:58Z

0

I think an if then else is going to get pretty messy if you have more than just a few of them. I prefer to use a switch. I think it makes the code easier to read but maybe that's a personal preference.

String currentUrl = "https://www.loca.com/usa/test/#/xxx";
String patternString1 = ".com\\/(\\w+)\\/";
Matcher matcher = Pattern.compile(patternString1).matcher(currentUrl);
if (matcher.find())
{
    String zipcode = "";
    switch (matcher.group(1))
    {
        case "usa":
            zipcode = "12345";
            break;
        case "canada":
            zipcode = "Ab1233";
            break;
        default:
            // handle an unexpected country
            break;
    }
}
else
{
    // handle the case of a bad URL
}

// do something with zipcode
System.out.println(zipcode);

edited Nov 11, 2016 at 5:40

answered Nov 11, 2016 at 2:21

JeffC

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1 Comment

JeffC Over a year ago

@BlackHatSamurai Yep, I tested it.

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