Memoizing a method on an object in TypeScript

Question

In JS I'd do:

var o = {
  foo: memoize(foo)
};

How do I do memoize an instance method in TypeScript similarly?

class C {
  // How do I memoize this function?
  public foo() :any {
  }
}

I want to use a class to fit in with the idioms established in the existing TypeScript codebase.

What's the intent of changing it into a class? Just because you're using TS doesn't mean you have to convert everything to classes. Write the JS you would have written anyway, and add type annotations where you want. — Ryan Cavanaugh
– Ryan Cavanaugh, Commented Nov 17, 2016 at 20:24
Can you return arbitrary objects from typescript class constructors? I ask because this is not my codebase and I need to leverage the Angular injector. Everytime I try and do something in TS I run into an unanticipated roadblock. — Ben Aston
– Ben Aston, Commented Nov 17, 2016 at 20:25
What does TS have to do with this? Classes are an ES6 feature. — Ryan Cavanaugh
– Ryan Cavanaugh, Commented Nov 17, 2016 at 20:28
This is a typescript codebase. Presumably I have to therefore write in TS. Or at the very least if I don't then I have to dodge the type errors and I am unsure if I know how to do that. — Ben Aston
– Ben Aston, Commented Nov 17, 2016 at 20:29

Ryan Cavanaugh · Accepted Answer · 2016-11-17 20:35:25Z

2

Here are two ways to do it:

// With Typescript syntax
class C {
  foo = memoize(() => {
  });
}

// Using ES6-style initialization instead of field initializers
class C {
    foo: () => any;
    constructor() {
        this.foo = memoize(() => {
        });
    }
}

answered Nov 17, 2016 at 20:35

Ryan Cavanaugh

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