How to call one external php file and pass the parameters using PHP

Question

I need one help. I need to pass some parameter to another php file and display it using PHP. I am explaining my code below.

user.php:

<?php
  $product_id=$_POST['product_id'];
?>

I need to pass this parameter ($product_id) to the following file by calling it.

saveUser.php:

<?php
  $newCustomerobj->product_id =$_REQUEST['product_id'];

  print_r($newCustomerobj);
?>

Here i need to pass the value from user.php to saveUser.php.Please help me.

if there is no navigation from user.php to saveUser.php then use session else encode the product it and through query string pass the variable. — Happy Coding
– Happy Coding, Commented Nov 23, 2016 at 9:01

Phoenix Dev · Accepted Answer · 2016-11-23 09:10:45Z

1

If it need not be secure, then pass it as a query string like saveUser.php?id=product_id and access it using $_GET['id'].

answered Nov 23, 2016 at 9:10

Phoenix Dev

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Comments

Nazmul Hasan · Accepted Answer · 2016-11-23 09:08:27Z

0

If you write a function as following

public function functionName($product_id, $variable 2,...)
{
   require_once ('saveUser.php');
}

Then usually all variable will get in saveUser.php file. I don't know if it can help you.

answered Nov 23, 2016 at 9:08

Nazmul Hasan

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