How to call anonymous function (Closure) from inline object?

Question

I need to quickly mock an object, so that when in template appears:

$that->user->isAdmin()

it will return true.

I tried to cast an array with anonymous function into object:

$that = (object) ( (array(
    'user'      =>
        (object) (array(
            'isAdmin' => function() {
                return true;
            }
(...)

but var_dump($that->user) returns an empty(?) Closure:

object(stdClass)#3 (1) {
  ["isAdmin"]=>
  object(Closure)#2 (1) {
    ["this"]=>
    object(View)#1 (0) {
    }
  }
}

and calling it directly by $that->user->isAdmin() returns Call to undefined method stdClass::isAdmin().

How can I rewrite $that in order to be able to call $that->user->isAdmin()?

Can be done in a dirty/hacky way, since it's only for a mocking purpose.

Federkun · Accepted Answer · 2016-11-28 16:25:22Z

1

$that->user->isAdmin is a propriety of the $that->user object, that's also a Closure. If you try to call it with $that->user->isAdmin(), you are trying to call the method isAdmin instead.

From php7 you can call it with

$bool = ($that->user->isAdmin)();

Otherwhise you can put $that->user->isAdmin in a variable and call it, or use call_user_func instead.

EDIT

If you want a method isAdmin:

$that = (object) ( (array(
    'user' => new class {
        public function isAdmin() {
            return true;
        }
    })
));

$bool = $that->user->isAdmin();

edited Nov 28, 2016 at 16:25

answered Nov 28, 2016 at 16:11

Federkun

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3 Comments

van_folmert Over a year ago

The tricky part is that it has to be called precisely by $that->user->isAdmin(), because it's a mock. I can only change $that object.

Federkun Over a year ago

then you don't need a closure, you need a method with that name

van_folmert Over a year ago

regarding your edit - is this construct from PHP7 as well? because I get unexpected 'class' (T_CLASS)

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