I have a incoming string like this :- *DDMMYYHHMMSS# DD Stands for Date, MM stands for month, YY stands for year, HH stands for Hour...
Example *021216213940# (Date : 2nd December, 2016 Time : 21:29:40)
How can I extract values from above given string and copy to int data type.
int Date,Month,Year,Hours,Minutes,Seconds;
You can use scanf family functions, like this:
char *incoming = "*021216213940#";
int day, month, year, hours, minutes, seconds;
if (6 != sscanf(incoming, "*%2d%2d%2d%2d%2d%2d#", &day, &month, &year, &hours, &minutes, &seconds))
{
... /* handle invalid input here */
}
sscanf can be used if the input is already located in a string. Like char* p = "*021216213940#"; if (6 != sscanf(p, "*%2d%2d%2d%2d%2d%2d#", &day, &month, &year, &hours, &minutes, &seconds)) { /* error handlind */ }To convert the content of your string you need to convert to (a two digit) decimal, which is a ten-based positional system.
For example to extract the first two digits you use subscript operator[], i.e. str[1] and str[2], to convert from char to int you subtract '0' character utilising ASCII character ordering and finally to ensure correct position of the digits you multiply by 10:
int DD = (str[1] - '0') * 10 + str[2] - '0';
int Date = (str[1] - '0') * 10 + str[2] - '0'.10to get the "tens". For example if the first digit is2then2 * 10 = 20.*021216213940# (Date : 2nd December, 2016 Time : 21:29:40). How to extract the date and month?