Counting each elements in list string

Question

I have a string -XX--XXX--XX- I'm trying to count each X and append it afterward. The above string should eventually be [2, 3, 2]. Here is a snippet of what I came up with:

knots = '-XX-XXX-XX-'

#Converting above string to ['XX', 'XXX', 'XX']
knots_without_dashes = knots.split('-')

For each 'X' in my list ['XX', 'XXX' and 'XX'] I want to count until the comma and append the result in an empty list without using counter library.

Hmm..I think you meant your output should be [2, 3, 2]? Might want to edit the question! Otherwise my answer is not correct. — Matt Morgan
– Matt Morgan, Commented Dec 1, 2016 at 23:45

Matt Morgan · Accepted Answer · 2016-12-02 00:07:26Z

1

[len(segment) for segment in knots.split('-') if len(segment)>0]

This will create a list made up of the length of each block that is separated by '-'.

edited Dec 2, 2016 at 0:07

answered Dec 1, 2016 at 23:28

Matt Morgan

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2 Comments

SoA Over a year ago

Appreciate the help, this is exactly what I'm looking for to also solve the second half of the whole problem :)

Matt Morgan Over a year ago

NP! It's a very 'pythonic' sort of a problem, so this feature, which is called a "list comprehension" is a typical solution.

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