How can I actually print out the ValueError's message after I catch it?
If I type except ValueError, err: into my code instead of except ValueError as err:, I get the error SyntaxError: invalid syntax.
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4 Answers
try:
...
except ValueError as e:
print(e)
6 Comments
Bengt
Note that in Python 3 you have to cast to string explicitly:
print(str(e)).
snapshoe
It's not true that you have to cast to string explicitly in Python 3. At least as of 3.5.
Happy
Note that in Python 3 you have to cast to string explicitly: print(str(e)), at least for Python 3.6.6
yair
@Bengt I think you should post it as an answer. Python 3.7.5 requires the cast
taskalman
I concur with @snapshoe, it isn't true, that the exception object has to be casted to a string before printing; you have this in the print function documentation: "All non-keyword arguments are converted to strings like
str() does". I can only assume, so please bear with me, but you might have done a concatenation like print('Error is: ' + str(e)) when the cast is indeed required, but that is because of the concatenation and not the print function. |
Another way of accessing the message is via args:
try:
...
except ValueError as e:
print(e.args[0])
Comments
Python 3 requires casting the exception to string before printing:
try:
...
except ValueError as error:
print(str(error))
3 Comments
snapshoe
This is still not true.
print(error) works just fine in that context in Python 3.
questionto42
@snapshoe If this is not true, why does it get upvoted? Perhaps there are cases where it is really needed? I doubt it, but who knows
lynkfox
@questionto42 using previous concating of strings causes this to be needed : ie:
print("Error: " + e) would fail if you do not cast the string. Using proper formatting: print(f"Error: {e}") works just fineAnother approach using logging
import logging
try:
int("dog")
except Exception as e:
logging.warning(e)
logging.error(e)
gives
WARNING:root:invalid literal for int() with base 10: 'dog'
ERROR:root:invalid literal for int() with base 10: 'dog'
[Program finished]
Just typing the exception gives,
invalid literal for int() with base 10: 'dog'
[Program finished]
Depends on how you want to process the output
