Asking user for input - prime number code [duplicate]

Question

num = 3    #take input from the user
if num > 1: # if input is greater than 1 check for factors
   for i in range(2,num):
       if (num % i) == 0:
               print(num,"is not a prime number")
               break
   else:
       print(num,"is a prime number")
            #if input number is less than or equal to 1, it is not prime

else:
   print(num,"is not a prime number")

I have my code here which works out the prime number of the num section, what I need to do it ask the user for the input when I run the code.

Did you do any searching at all?

Karnage
– Karnage

2016-12-07 09:31:45 +00:00
Commented Dec 7, 2016 at 9:31 — Karnage
– Karnage, Commented Dec 7, 2016 at 9:31

ForceBru · Accepted Answer · 2016-12-07 09:31:33Z

0

This is pretty straightforward:

num = int(input("Input a number: "))

answered Dec 7, 2016 at 9:31

ForceBru

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4 Comments

Seif Over a year ago

No need for the int() unless you want to handle errors

ForceBru Over a year ago

@Saksow, the OPs code is clearly in Python 3.x

Klaus D. Over a year ago

@Saksow That depends on the Python version. Casting it to an int will make it work in Python 2 and 3.

Guillaume Over a year ago

Python 2 input() evaluates the user input as an expression, raw_input() returns a string. Python 3 input() returns a string no matter what.

Taufiq Rahman · Accepted Answer · 2016-12-07 09:33:35Z

0

Since input() always assumes that it's taking a string ,you have to convert it to int :

print("Enter a number:")
num = int(input())   #this here
if num > 1: # if input is greater than 1 check for factors
   for i in range(2,num):
       if (num % i) == 0:
               print(num,"is not a prime number")
               break
   else:
       print(num,"is a prime number")
            #if input number is less than or equal to 1, it is not prime

else:
   print(num,"is not a prime number")

answered Dec 7, 2016 at 9:33

Taufiq Rahman

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