Extracting version information using Regex

Question

I need to extract version information from the following string

993-756-V01 ver 02a

What regex I need to use in order to extract 01 and 02 from 993-756-V01 ver 02a

I tried to extract the version substring i.e. V01 ver 02a with the below regex.

[A-Z][0-9]{2} ver [0-9]{2}

But is there a more direct way to extract the information

I suggest adding groups: [A-Z](?<major>[0-9]{2}) ver (?<minor>[0-9]{2}) — Dmitrii Bychenko
– Dmitrii Bychenko, Commented Dec 7, 2016 at 10:09
@DmitryBychenko: How do I achieve grouping when it doesn't recognise the <major> and <minor> entries beforehand. Do you mean this way [A-Z]([0-9]{2}) ver ([0-9]{2}) — this-Me
– this-Me, Commented Dec 7, 2016 at 10:36
@this-Me: What do you mean by it doesn't recognise the <major> and <minor> entries beforehand? The regex matches and captures the necessary details into the "major" and "minor" groups. See Dmitry's regex demo. You may also use [A-Z](?<major>[0-9]+) ver (?<minor>[0-9]+) — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Dec 7, 2016 at 10:37

Wiktor Stribiżew · Accepted Answer · 2016-12-07 13:16:59Z

1

You may use a regex with named capturing groups to capture the information you need. See the following code:

var s = "993-756-V01 ver 02a";
var result = Regex.Match(s, @"(?<major>[0-9]+)\s+ver\s+(?<minor>[0-9]+)");
if (result.Success)
{
    Console.WriteLine("Major: {0}\nMinor: {1}", 
        result.Groups["major"].Value, result.Groups["minor"].Value);
}

See the C# demo

Pattern details:

(?<major>[0-9]+) - Group "major" capturing 1+ digits
\s+ - 1+ whitespaces
ver\s+ - ver substring and then 1+ whitespaces
(?<minor>[0-9]+) - Group "minor" capturing 1+ digits

answered Dec 7, 2016 at 13:16

Wiktor Stribiżew

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2 Comments

this-Me Over a year ago

Thanks for simplifying this for me. I had over complicated the groups using Linq this way <code>

foreach (Match match in matchCollection)                 {                     List<Group> groupList = new List<Group>(match.Groups.Cast<Group>());                     Group[] groupResult = groupList.Where((n) => n.Length == 2).ToArray<Group>();                     if (groupResult.Length > 1)                     {                         majorVersion = groupResult[0].Value;                         minorVersion = groupResult[1].Value;                     }                 }

</code>

Wiktor Stribiżew Over a year ago

Yes, that is a lot of redundant code. If my answer proved helpful, please also consider upvoting the answer.

NeverHopeless · Accepted Answer · 2016-12-07 14:29:45Z

1

Another short possibilility i see is to use the below pattern:

V(\d+)\D+(\d+)

Here:

V     = Literal `V` capital alphabet.
(\d+) = Captures any digit from 0-9 following `V` character. 
\D+   = Anything except digit next to digits. (A way to find the next numeric part of your version number)
(\d+) = Captures any digit from 0-9 following non-digit characters.

Demo

answered Dec 7, 2016 at 14:29

NeverHopeless

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