Array
(
[0] => 'hello'
[1] => 'there'
[2] =>
[3] =>
[4] => 3
)
// how to get the number 5?
-
I was looking at my own code wrong which made me think that count ignored null values.Mohammad– Mohammad2010-11-05 14:05:45 +00:00Commented Nov 5, 2010 at 14:05
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6 Answers
$arr = Array
(
0 => 'hello',
1 => 'there',
2 => null,
3 => null,
4 => 3,
);
var_dump(count($arr));
Output:
int(5)
2 Comments
nikc.org
count(array_keys($arr)) then perhaps?
RobertPitt
In the sample, even if keys (2,3) are empty, count will still count them as they exists.
count($arr) even if there false,null,0,"" etc, aslong as they exists count() will add them up, As MatTheCat says, echo count(array(1,null,null)); gives 3
Works for me w/ NULL
$array = array('hello', 'there', NULL, NULL, 3);
echo "<pre>".print_r($array, true)."</pre><br />";
echo "Count: ".count($array)."<br />";
output
Array
(
[0] => hello
[1] => there
[2] =>
[3] =>
[4] => 3
)
Count: 5
A quick Google search for PHP Array should pull up results of all the functions available
Comments
Below code was tested with PHP 5.3.2. and the output was int 5.
$a = array(
0 => 'hello',
1 => 'there',
2 => null,
3 => null,
4 => 3,
);
var_dump(count($a));
Can you please provide more information about null not being counted? An older version maybe? Or simply messing with the rest of us? :)
EDIT: well, posted wrong code :)
Comments
echo count($array);
Comments
If you want to try something different you can also do it by getting the max array key and adding +1 to account for the first array starting with zero.
$count = max(array_keys($my_array))+1;
echo $count;
