change a part of file via regex and java

Question

I have 2 different results betwin regex online and my java code.

My input text:

Examples:
    #DATA
    |id|author|zip|city|element|
    Odl data - Odl data - Odl data    
    #END

I want change Odl data - Odl data - Odl data (in my example) by foo.

My regex is:

#DATA[\s\S].*[\s\S]([\s\S]*)#END

I want change Group 1 by foo

démo online:

https://regex101.com/r/Nq9fas/2

My java code:

final String regex = "#DATA[\\s\\S].*[\\s\\S]([\\s\\S]*)#END";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);

if (matcher.find()) {
    System.out.println("Full match: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
        System.out.println("Group " + i + ": " + matcher.group(i));
    }
}

See regex101.com/r/Qllz0P/1

Wiktor Stribiżew
– Wiktor Stribiżew

2016-12-17 14:08:25 +00:00
Commented Dec 17, 2016 at 14:08 — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Dec 17, 2016 at 14:08

Wiktor Stribiżew · Accepted Answer · 2016-12-17 14:13:37Z

1

The point is to match what you need to remove/replace and match and capture what you need to keep.

You may use a replaceFirst with

(#DATA\r?\n.*\r?\n)[\s\S]*(#END)

See the regex demo. In Java:

String res = s.replaceFirst("(#DATA\r?\n.*\r?\n)[\\s\\S]*(#END)", "$1foo\n$2");

Note: If you have only one 1 line to replace, use

(#DATA\r?\n.*\r?\n).*([\s\S]*#END)

Note 2: If you have several such "blocks" in the text, use a lazy quantifier with [\s\S] and use with replaceAll instead of replaceFirst:

(#DATA\r?\n.*\r?\n).*([\s\S]*?#END)
                            ^^

answered Dec 17, 2016 at 14:13

Wiktor Stribiżew

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