How do I split a string and store it in a list?

Question

I have a string a="100111" and want to split it and store as b=("1","0","0","1","1","1") as a list with length =6. I tried splitting using srtsplit but I end up with a list b = ("1" "0" "0" "1" "1" "1"), with length = 1. The end goal is to get which positions in the string "100111" has 1. For example when I split a and store it in b as ("1","0","0","1","1","1") and then use which(b=='1') it want to get (1,4,5,6)

which(unlist(strsplit(a, split="")) == 1) will do it. you have to pull the vector out of the list with unlist. — lmo
– lmo, Commented Dec 23, 2016 at 13:49

G. Grothendieck · Accepted Answer · 2016-12-23 13:59:16Z

5

gregexpr will give the positions of 1's in the string without having to actually split it:

unlist(gregexpr("1", "100111"))
## [1] 1 4 5 6

answered Dec 23, 2016 at 13:59

G. Grothendieck

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1 Comment

lmo Over a year ago

Nice. I Keep forgetting about those regex functions.

akrun · Accepted Answer · 2016-12-23 15:17:16Z

0

Another option is str_locate from stringr

library(stringr)
str_locate_all(a, "1")[[1]][,1]
#[1] 1 4 5 6

answered Dec 23, 2016 at 15:17

akrun

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