MalformedURLException: unknown protocol: http

Question

I am trying to call a servlet from an Oracle DB and for that I am using a java 1.4 class with an URL call on this form http://ip:80/serv/Servletg?parameter with

url = new URL("http","ip",80,"/serv/Servletg"+parameter);

and the following exception is occurred:

java.net.MalformedURLException: unknown protocol: http at java.net.URL.(URL.java:376)
at java.net.URL.(URL.java:264)

With using a webbrowser the URL is giving a good response from the webserver.

I can not understand what the problem in this issue. I am using apache Tomcat on the webserver side.

Thanks for Help

Do you get the same error if you use the URL overload that only takes a string? IE url = new URL("ip:80/serv/Servletg?parameter"); ? — Khalos
– Khalos, Commented Nov 9, 2010 at 11:07
yes I have the same Error with url = new URL("ip:80/serv/Servletg?parameter"); — Haythem
– Haythem, Commented Nov 9, 2010 at 11:20

dacwe · Accepted Answer · 2010-11-09 11:33:43Z

1

You must add the correct security permissions to get it to work - seems that you are not allowed to access the network!

See http://download.oracle.com/docs/cd/B14117_01/java.101/b12021/security.htm

edited Nov 9, 2010 at 11:33

answered Nov 9, 2010 at 11:16

dacwe

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5 Comments

Haythem Over a year ago

It works with the webbrowser without https. Do you mean that I need a security permission on Oracle?

dacwe Over a year ago

Maybe I understood you wrong but this is what I think happens: You have an oracle DB running a java method for you right? Problably Oracle uses javas built in permissions when running this method. If not, who is running the method/class?

dacwe Over a year ago

Added a url to something interesting.. :)

Haythem Over a year ago

I tried the https but the compile is givign me the same error java.net.MalformedURLException: unknown protocol: https at java.net.URL.<init>(URL.java:376) at java.net.URL.<init>(URL.java:264)

dacwe Over a year ago

No no, it is not a secure protocol you need. The java code is not allowed to connect at all using external protocols - look at the link.

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