Syntax Error in Python compiling (Mac Os - Terminal)

Question

I just watched a video on YouTube in which they discuss about the maths of the Monopoly game, and besides all the things, they added the Python code in the download box, hence I downloaded it to try it...

This is the code:

import random
from random import shuffle

def monop(finish_order=6,games_order=3):

    finish = 10**finish_order
    games = 10**games_order

    squares = []

    while len(squares) < 40:
        squares.append(0)

    # roll values are values from a six by six grid for all dice rolls
    rollvalues = [2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12]

    games_finished = 0

    while games_finished < games:

        master_chest = [0,40,40,40,40,10,40,40,40,40,40,40,40,40,40,40]
        chest = [i for i in master_chest]
        shuffle(chest)

        master_chance = [0,24,11,'U','R',40,40,'B',10,40,40,5,39,40,40,40]
        chance = [i for i in master_chance]
        shuffle(chance)

        doubles = 0

        position = 0

        gos = 0

        while gos < finish:

            diceroll = int(36*random.random())

            if diceroll in [0,7,14,21,28,35]:    # these are the dice index values for double rolls
                doubles += 1
            else:
                doubles = 0
            if doubles >= 3:
                position = 10
            else:

                position = (position + rollvalues[diceroll])%40

                if position in [7,22,33]:  # Chance
                    chance_card = chance.pop(0)
                    if len(chance) == 0:
                        chance = [i for i in master_chance]
                        shuffle(chance)
                    if chance_card != 40:

                        if isinstance(chance_card,int):
                            position = chance_card
                        elif chance_card == 'U':
                            while position not in [12,28]:
                                position = (position + 1)%40
                        elif chance_card == 'R':
                            while position not in [5,15,25,35]:
                                position = (position + 1)%40
                        elif chance_card == 'B':
                            position = position - 3

                elif position in [2,17]:  # Community Chest
                    chest_card = chest.pop(0)
                    if len(chest) == 0:
                        chest = [i for i in master_chest]
                        shuffle(chest)
                    if chest_card != 40:
                        position = chest_card

                if position == 30: # Go to jail
                    position = 10


            squares.insert(position,(squares.pop(position)+1))

            gos += 1

        games_finished += 1


    return squares

Called: monopoly-v1.py

Now, when I try to compile and run it into the terminal I get "problems".

By writing

python monopoly-v1.py

in the terminal, I don't get any error or warning, but it does not happen anything...

If I try with

python monopoly-v1.py

and then

./monopoly-v1.py

then here is what it says:

./monopoly-v1.py: line 1: syntax error near unexpected token (' ./monopoly-v1.py: line 1:def monop(finish_order=6,games_order=3):'

I don't understand what is wrong. By the way, python or python3 are the same, I mean: no error appears at the first step.

Any idea?

Thank you!

The code you've presented consists of just one Python function. There's no code to 'make it go', so to speak. — Bill Bell
– Bill Bell, Commented Dec 27, 2016 at 13:46

ForceBru · Accepted Answer · 2016-12-27 14:03:20Z

4

This code is merely a function definition and some imports. It will do nothing if you don't run that function. This is why python script.py doesn't show anything.

Now, when you try to do this:

./script.py

The shell tries to execute Python code as if it was written in BASH (or, more generally, as if it was a shell script), which results in an error, of course. Why does it do so? Because it's told to execute via the ./ structure, but cannot find anything to execute it with¹. So, it finally tries to run it as a shell script.

_{1. And the shell actually does the search. For example, if you prefixed your code with a special shebang, it would try to run it as Python code: #!python or #!env python or #!/usr/bin/env python or even #!/path/to/python}

edited Dec 27, 2016 at 14:03

answered Dec 27, 2016 at 13:58

ForceBru

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Comments

valepert · Accepted Answer · 2016-12-27 14:06:06Z

2

just add:

if __name__ == '__main__':
    monop()

at the end of monopoly-v1.py

answered Dec 27, 2016 at 14:06

valepert

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2 Comments

EXVII Over a year ago

I tried to do that, but when I compile it takes forever (no response..)

EXVII Over a year ago

@ForceBru I don't think your comment helped me somehow.

Wes Doyle · Accepted Answer · 2016-12-27 14:17:29Z

2

You have not called any function you wish to execute. If you would like to call the monop function from the command line, you might do so by using the -c argument:

$ python -c 'from monopoly-v1 import monop; print monop(6, 3)'

Note that the print function syntax will be different if using Python 3:

$ python -c 'from monopoly-v1 import monop; print(monop(6, 3))'

edited Dec 27, 2016 at 14:17

answered Dec 27, 2016 at 14:01

Wes Doyle

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5 Comments

Wes Doyle Over a year ago

What is your syntax error? The command line syntax here is correct.

EXVII Over a year ago

File "<string>", line 1 from monopoly-v1.py import monop; print monop(6, 3) ^ SyntaxError: invalid syntax

Wes Doyle Over a year ago

Are you using python 3?

EXVII Over a year ago

I can use both of them, if you are asking about what version does my computer support

Wes Doyle Over a year ago

I am asking which version you are using to attempt to run this code, clearly; >> print(foo) is python 3 syntax, >>print foo only works in python 2

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