Shell Script, commandline arguments

Question

the task is to write a shell script inputs are a string and a number

for example,

xxx.sh "Hello World" 3

the input will be

***************
* Hello World *
* Hello World *
* Hello World *
***************

and here is what have I got so far:

function mantra()   {
    echo "string is $1"
    echo "number is $2"

    echo $string
    echo $PATH
    for num in string_length; do
        echo "*"
    done
}

How do I count the number of characters in the string? Am I doing right? I am not exactly sure how to pass command-line arguments into my function.Blockquote

Reese Moore · Accepted Answer · 2010-11-09 16:25:13Z

1

The number of characters in your input string is ${#1}

See this page for a short explanation.

answered Nov 9, 2010 at 16:25

Reese Moore

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Brad · Accepted Answer · 2010-11-09 16:41:14Z

0

#!/bin/sh

function mantra()   {

    string=$1
    num=$2

    strlen=${#string}

    let strlen=$strlen+2


    echo -n "*"
    for (( times = 0; times < $strlen; times++ )); do echo -n "*" ; done

    echo "*";


}

mantra $1 $2

    for (( times = 0; times < $num; times++ )); do
        echo "* $string *"
    done

mantra $1 $2

answered Nov 9, 2010 at 16:41

Brad

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