PHP OOP: Is it possible to pass parameters to a class __destruct?

Question

If needed, parameters can be passed to a class via it's constructor.

class Test {

  public function __construct($echo) {
    echo $echo;
  }

}

$test = new Test('hello'); // Echos "hello"

Is there any way of passing parameters to the __destruct?

class Test {

  public function __construct($echo) {
    echo $echo;
  }

  public function __destruct($string) { // Is this possible?
    // Do something with this string
  }

}

Hanky Panky · Accepted Answer · 2016-12-30 04:00:03Z

2

No, Destructors have only one signature

void __destruct ( void )

Manual

answered Dec 30, 2016 at 4:00

Hanky Panky

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1 Comment

MultiDev Over a year ago

Thanks, I couldn't seem to find that anywhere.

Shinji Yamada · Accepted Answer · 2016-12-30 04:04:45Z

1

It's not possible. But you can use a instance field like this:

class Test {
  var $value;
  public function __construct($echo) {
    this->value = $echo;
  }
  public function __destruct() {
    echo $this->value;
  }
}

answered Dec 30, 2016 at 4:04

Shinji Yamada

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