TypeError: an integer is required while using replace() in python

Question

I'm trying to parse a date and put it in the correct format, this is what I tried so far:

import csv
import sys
import os
import re
import fnmatch
import csv
from dateutil.parser import parse as parseDate
from datetime import datetime, time, timedelta

chaine = '16/12/201602:15:00'
date = chaine[:10] + " " + chaine[11:]
print date
newd = parseDate(date, yearfirst=True)
print newd
newd = newd.replace('-','')
newd = newd.replace(':','')
print newd

This is what I get as result:

16/12/2016 2:15:00
2016-12-16 02:15:00
Traceback (most recent call last):
  File "t.py", line 25, in <module>
    newd = newd.replace('-','')
TypeError: an integer is required

What do I miss here?

Thank you

newd is not a string. Try using newd = str(newd).replace('-','') instead of newd = newd.replace('-',''). — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jan 4, 2017 at 8:50
thank you! could you put an answer so that i can accept it :) — JavaQueen
– JavaQueen, Commented Jan 4, 2017 at 8:54
if your date is '16/12/201602:15:00', then your setting for yearfirst in parseDate(date, yearfirst=True) seems to be wrong too, but without effect on the result, so you can drop that option — Maarten Fabré
– Maarten Fabré, Commented Jan 4, 2017 at 9:12

Wiktor Stribiżew · Accepted Answer · 2017-01-04 09:27:55Z

8

To fix your current logic, you need to cast the newd variable to a string after parseDate:

newd = str(newd).replace('-','')
       ^^^^^^^^^

See the Python demo

Alternatively, use the strptime / strftime:

from dateutil.parser import parse as parseDate
from datetime import datetime, time, timedelta
from time import strftime

chaine = '16/12/201602:15:00'
dt = datetime.strptime(chaine, '%d/%m/%Y%I:%M:%S')
# 16/12/2016 2:15:00
print(dt.strftime("%Y/%m/%d %H:%M:%S"))
#2016-12-16 02:15:00
print(dt.strftime("%Y-%m-%d %H:%M:%S"))
# 20161216 021500
print(dt.strftime("%Y%m%d %H%M%S"))

See another Python demo.

edited Jan 4, 2017 at 9:27

answered Jan 4, 2017 at 8:58

Wiktor Stribiżew

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2 Comments

Maarten Fabré Over a year ago

better would be to use strftime

Wiktor Stribiżew Over a year ago

@MaartenFabré: Yes, I know, just did not have time to prepare a demo. Added now.

pirela · Accepted Answer · 2017-01-04 09:06:04Z

0

In your code newd is a datetime.datetime object, not a string. you can see it with

print type(newd)  shows <type 'datetime.datetime'>

so you cannot use a string replacement.
you can use discrete properties like

 newd.year .month .day etc.

to create your own string.( more on Python doc )
or play more quickly with the strftime method

answered Jan 4, 2017 at 9:06

pirela

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