How to replace multiple characters in swift 3

Question

I'm trying to convert the parts of code that Xcode couldn't convert to Swift3

In swift 2.3 to replace multiple characters in a string I used :

var phone = "+ 1 (408)-456-1234"
phone = phone.replaceCharacters("  ) ( -   ‑", toSeparator: "")

this should give +14084561234

In swift 3 I'm using this :

phone = phone.replacingOccurrences(of: " |(|)|-", with: "z",options: .regularExpression)

this code gives +1(408)4561234

How to replace multiple characters in a string (Swift3)?

but this is not working correctly ? any ideas

Could you please describe what exactly you want to do? It's obvious your Swift 3 code doesn't contain a valid regular expression. — Sulthan
– Sulthan, Commented Jan 8, 2017 at 16:54

Sulthan · Accepted Answer · 2017-01-08 17:11:15Z

16

You have to fix the regular expression to create a set of characters you want to remove, e.g.:

var phone = "+ 1 (408)-456-1234"
phone = phone.replacingOccurrences(of: "[ |()-]", with: "", options: [.regularExpression])
print(phone) // +14084561234

but a better solution is to create a set of characters you want to keep and remove all the others:

phone = phone.replacingOccurrences(of: "[^\\d+]", with: "", options: [.regularExpression])

answered Jan 8, 2017 at 17:11

Sulthan

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Comments

JMI · Accepted Answer · 2017-01-08 17:13:36Z

5

Brackets in regular expressions means group. By other words they have to be escaped:

var phone = "+ 1 (408)-456-1234" 
phone = phone.replacingOccurrences(of: " |\\(|\\)|-", with: "",options: .regularExpression)
// "+14084561234"

But it can be simplified by enumeration of characters:

var phone = "+ 1 (408)-456-1234" 
phone = phone.replacingOccurrences(of: "[-() ]", with: "",options: .regularExpression)
// "+14084561234"

answered Jan 8, 2017 at 17:13

JMI

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Comments

gondo · Accepted Answer · 2020-04-21 07:58:06Z

0

Swift 5

var phone = "+ 1 (408)-456-1234"
let characterSet = CharacterSet(charactersIn: " )(-‑")
phone = phone.components(separatedBy: characterSet).joined(separator: "")

answered Apr 21, 2020 at 7:58

gondo

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