For each odd item in php array

Question

I am trying to print every 2nd item or an array starting with 1 so the 1st, 3rd, 5th element etc. My current code give illegal offset type error

$array2 = array(explode(',', $prodorder));

<?php foreach($array2 as $value) { 
    if ($value % 205 !== 0) {

        $productscore =  $_POST[$value];
        echo $value;
?>

    <tr><td><?php echo $productname;?></td><td><?php    echo $productdescription;?></td></tr>

    <?php }} ?>

Chin Leung · Accepted Answer · 2017-01-22 22:16:57Z

2

Use a for loop instead.

for($i=0; $i<count($items); $i+=2)
    echo $items[$i] . '<br>';

answered Jan 22, 2017 at 22:16

Chin Leung

15k4 gold badges38 silver badges64 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Innov Bee Over a year ago

I have changed to the above but this isn't echoing out anything. My array values are 1,2,4,9 and I am expecting 1 and 4 to be echoed

Daniel Lagiň · Accepted Answer · 2017-01-22 22:29:39Z

0

This will also work, but using for loop is better and more elegant way.

$array2 = [
  "value1",
  "value2",
  "value3",
  "value4",
  "value5"  
];  
//$array2 = array_values($array2);

foreach($array2 as $k => $v) { 
   if (($k + 1) % 2 == 1) {   
       echo $v;
   }  
}

Also this cant be used in associative array, unless you use array_values.

edited Jan 22, 2017 at 22:29

answered Jan 22, 2017 at 22:18

Daniel Lagiň

7387 silver badges19 bronze badges

Comments

DeepBlue · Accepted Answer · 2017-01-22 22:31:59Z

0

Try this:

foreach($array2 as $k=>$value) { 
    if ($k % 2 !== 0) {
        $productscore =  $_POST[$value];
        echo $value;
    }
}

answered Jan 22, 2017 at 22:31

DeepBlue

6948 silver badges24 bronze badges

Collectives™ on Stack Overflow

For each odd item in php array

3 Answers 3

1 Comment

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related