Reading .csv file into an array in C [duplicate]

Start by defining your data structure:

struct my_record {
    char name;
    int value;
};

Then you can read like this:

FILE* my_file = fopen(...);
struct my_record records[100];
size_t count = 0;
for (; count < sizeof(records)/sizeof(records[0]); ++count)
{
    int got = fscanf(my_file, "%c,%d", &records[count].name, &records[count].value);
    if (got != 2) break; // wrong number of tokens - maybe end of file
}
fclose(my_file);

Now you have a 1D array of structs, one for each row.

You can just create an array of structs, as the other answer described.

Once you have the struct definition:

typedef struct {
    char letter;
    int number;
} record_t;

Then you can create an array of structs like this:

record_t records[26]; /* 26 letters in alphabet, can be anything you want */

Using a 2D array would be unnecessary, as wrapping the letter and number in a struct would be easier to handle.

In terms of reading your file, you can just read with fscanf() until 2 values are not found.

Here is some basic code you can use:

#include <stdio.h>
#include <stdlib.h>

#define NUMLETTERS 26

typedef struct {
    char letter;
    int number;
} record_t;

int main(void) {
    FILE *fp;
    record_t records[NUMLETTERS];
    size_t count = 0;

    fp = fopen("letters.csv", "r");
    if (fp == NULL) {
        fprintf(stderr, "Error reading file\n");
        return 1;
    }

    while (fscanf(fp, " %c,%d", &records[count].letter, &records[count].number) == 2) {
        count++;
    }

    for (size_t i = 0; i < count; i++) {
        printf("%c,%d\n", records[i].letter, records[i].number);
    }

    fclose(fp);

    return 0;
}